For all you who think you're good -help!

First posting: Wednesday, 12 February 2003 11:46:56 PM

J

Prove that [(1900^1990) - 1] is divisible by 1991
RESPONSES

shy boy | (200.78.57.100) | Friday, 22 August 2003 8:09:24 AM
Whats up?

James | (211.30.109.158) | Saturday, 21 August 2004 8:53:48 PM
The divisible series for 1990 marches along thus: 1990, 2x1990, etc The divisible series for 1991 marches along thus: 1991, 2x1991, etc The steps for 1990 fall behind the steps for 1991 by exactly 1 for each step. In 1991 steps they will match ie 1991x1990. In 1990 steps, the 1990 series will still be 1 ahead of the 1989th step of the 1991 series. Therefore removing 1 will generate a factor of 1991.

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